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See MIRA explainMIRA’s boardPhysicseV = ½ m v²
An electron is accelerated through a potential difference V and enters a magnetic field B. What is the radius of its circular path?
Energy gained = kinetic energy, so v = √(2eV/m).
Magnetic force = centripetal force: mv²/r = evB, so r = mv/(eB).
Substituting v, r = √(2Vm / eB²).